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2014-07-31 19:11:19 -0600 | answered a question | Final Review Number one Ok, you take each point one at a time and get your values for a,b,c.
Starting with $ax + by + cz = 4$ and the point $( ... |
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2014-07-31 06:36:23 -0600 | answered a question | Final Review If you bring the 4 to the other side you get $x^2 + y^2 = 4$, which is a circle of radius 2. For this reason, I set this ... |
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2014-07-30 12:25:57 -0600 | answered a question | quiz 3 question 1 My answer was slightly different because when you u-sub you have to change your bounds of integration.
I'll start here ... |
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2014-07-29 20:01:54 -0600 | answered a question | Review for final Exam This is how I solved this problem:
I left $\vec{p}(t)$ in terms of $t$ and changed the parameter of $\vec{q}$ to $s$. I ... |
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2014-07-29 09:38:44 -0600 | answered a question | Line Integrals Anonymous, the first thing I noticed was your bounds of integration. I posted a question about this last night as I was ... |
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2014-07-28 16:41:58 -0600 | answered a question | Number 6 on Exam 2 I actually missed this one on the exam, but since then have worked on what the contour diagram would look like. This sho ... |
2014-07-28 12:06:32 -0600 | asked a question | How do I get the bounds of integration for line integrals? I am currently working on the homework for 16.2. Number one, for example, states: "Compute $\int\limits_Cxy^2ds$ along t ... |
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2014-07-25 16:06:35 -0600 | answered a question | Setting up spherical integrals I don't really know if my answer will be easily explainable but I will try to explain it as I understand it. With spheri ... |
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2014-07-24 18:58:35 -0600 | answered a question | Quiz question Yes, I asked this question earlier because I was struggling with the set up for Cartesian land.
It was one of the ones ... |
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2014-07-24 14:52:49 -0600 | asked a question | Setting up exponential function in Cartesian coordinates I am hoping for some help looking at the exponential function in Cartesian land.
If we are given $e^{-(x^2+y^2)}$ and ... |
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2014-07-23 11:45:41 -0600 | answered a question | In class Problem The way our group set it up was different, and here is why.
The domain is only the top half of the unit sphere, so $\d ... |
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2014-07-19 06:19:32 -0600 | answered a question | Post-test analysis Just wanted to chime in here, too. I also got (-1,0) and (1,0) for the maxima and I too noticed that this did not line u ... |
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