Review for final Exam
I was looking back over Exam 1 and question number ten is still giving me a problem. Can someone please explain the right path that I should have taken to get the right answer? The question was Let $p(t)=<1+3t, 2+4t>$ and let $q(t)=<3-t, -4+3t>$. Find the point of intersection between the paths parametrized by p and q. What I attempted was to solve for u and t $$1=3t+3-u \rightarrow -2+3t=-u \rightarrow (2-3t)=u$$ $$2+4t=-4-3u$$ $$2+4t=-4-3(2-3t)$$ $$6+4t=-6+9t$$ $$12=5t$$ $$t=12/5$$ but then I don't know what to do complete the problem after that.