BDR

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BDR
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  • My matrix:[ [0, 4, 2, 2, 1], [1, 0, 4, 4, 1], [1, 3, 0, 4, 4], [1, 3, 2, 0, 1], [2, 1, 4, 1, 0] ] Team 3: rating = 0.5317387251068555 Team 2: rating = 0.4743664736534873 Team 1: rating = 0.43963279846587106 Team 5: rating = 0.41258201033241837 Team 4: rating = 0.3587888852214044 Clearly, team 3 has the advantage. However,…
    in Eigenranking Comment by BDR March 2021
  • For my conditions, $k=0$ and $f=0$, the steady-state of my polygon is shown below. The temperature in the lower right hand corner $(28.69,0.93)$, is approximately $u=0.92895$.
  • Per the screenshot above, the temperature near the midpoint of the insulated side of the triangle is approximately 0.04795. See my random questions for more details.
  • A metal bar of length 1 lies along the unit interval. Its temperature distribution is given by $g(x) = 4x^2 - 2x$. At time t=0, its left end is set to temperature 2 and its right end to 0. Sketch the temperature distribution at times t=0, t=0.01, t=0.1, and t=10
  • Heat flow with a constant internal heat source is governed by: $u_t=2u_{xx}+7$, $u(0,t)=−2$, $u(1,t)=4$. Because this is a steady state temperature distribution, $u_t=0$ since $u(x,t)$ does not change with time. So, $0=2u_{xx}+7$ Solving for $u_{xx}$ gives $u_{xx}=\frac{-7}{2}$. By integrating this equation twice we get:…
  • The displacement of the midpoint from the equilibrium is approximately 0.358 when t=1.7