Number 10 on the review sheet
asked 2014-07-02 14:01:57 -0600
Hey, guys. Here's where I am with this one. First I solved for a normal vector $$n=\langle p_{1}-p_{2} \rangle \times \langle p_{3}-p_{2}\rangle $$$$= (\langle 1,-2,3 \rangle - \langle -1,2,2 \rangle) \times (\langle 1,1,2 \rangle - \langle -1,2,2 \rangle)$$$$=\langle 2,-4,1 \rangle \times \langle 2,-1,0 \rangle$$$$=\langle 1,2,6 \rangle$$ Then I define a p nought $$p_{0}=p_{1}=\langle 1,-2,3 \rangle$$ So if I let the coefficients of the plane equation be the components of the normal vector I end up here. $$(x-1)+2(y+2)+6(z-3)=0$$$$x+2y+6z=21$$ So I guess the question is did everyone else get the same result? If not how did you do the problem? Is this the best method or is there a simpler way?
