Question #2 on quiz
I don't remember the exact wording of question #2 on the quiz but I think it asked what the area above the curve $z=-\sqrt{x^2+y^2}$ and below $z=\sqrt{x^2+y^2}$ inside the cylinder $x^2+y^2=1$; evaluate $\int\int\int (z) dV$.
My answer came out to be zero but I don't think that is correct. If anybody understands this problem or has any ideas, please post them.