Series and elementary function problems
Recall that we showed that \(\zeta(z)=\eta(z)/(1-2^{1-z})\). I’ve also stated (without proof) a couple of times that \[ \zeta(2) = \sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6} \text{ and } \zeta(4) = \sum_{n=1}^{\infty} \frac{1}{n^4} = \frac{\pi^4}{90}. \] Use those facts to find closed-form expressions for \[ \eta(2) = \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n^2} \text{ and } \eta(4) = \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n^4}. \]
Use the definition of the exponential function to show that
- \(|e^z| \leq e^{|z|}\)
- \(\displaystyle \lim_{z\to0} \frac{e^z-1}{z} = 1\)
Compute the values of the following:
- \(\text{Log}(\sqrt{3}+i)\)
- \(\log(8i)\)
- \((1+i)^{\pi i}\)
- \(2^i\)