đťš·, circumference, and area
Both the circumference and area of a circle are related to the fundamental constant \(\pi\) by \[C = 2\pi r \text{ and } A = \pi r^2.\] The circumference formula is, in fact, the very definition of \(\pi\) but the area formula is much deeper. From the perspective of calculus, the area computation looks a lot like a Riemann sum!
\(\pi\) and circumference
Most students probably know that the circumference of a circle is related to its radius by \[C = 2\pi r.\] This is, in fact, pretty much the definition of \(\pi\). That is, given any two circles, the ratio of their circumference to their diameter is the same. This is a fundamental characteristic of geometric similarity. This common value is, by definition, denoted by the symbol \(\pi\).
That is \(\displaystyle \pi = C/(2r)\), for any circle.
We can use this to approximate \(\pi\) by inscribing a polygon into a circle of radius 1. The perimeter of the polygon is just a collection of line segments so we can compute its value by adding the lengths of the line segments. Using six sides shows that \(\pi\) is a bit bigger than three. Using more sides yields a better estimate, as the demo below shows.
\(\pi\) and area
We’ve now seen that \(\pi\) and circumference are related basically by definition. It’s a bit trickier to see how \(\pi\) is related to area, even though we certainly all know the formula: \[ A = \pi r^2. \] It was Archimedes Circa 200 BC who first derived this formula. The following demonstration, though, is generally attributed to Leonardo da Vinci during the 15th century. From the perspective of calculus, it has the advantage of a clear relationship with Riemann sums.
Given a circle of radius \(r\), we break it into a collection of an even number of wedges. These wedges can be rearranged into a configuration that approaches a rectangle as the number of wedges increases. It’s pretty easy to see that the dimensions of that rectangle are the radius of the circle by half the circumference of the circle. That is, it’s area is \[ r \times \pi r = \pi r^2. \]