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I think that I understand how to set up the domain of this integral except for the inner integral. The question asks: "Let $D$ denote the set in $\mathbb{R^3}$ lying above the cone $z=\sqrt{x^2+y^2}$ and inside the sphere $x^2+y^2+z^2=4$. Set up the following integrals over $D$ as iterated integrals in spherical coordinates. You should think about which ones you can evaluate."

would this be correct?: $$\int_0^\pi \int_0^\frac{\pi}{4} \int_0^2 (\rho^2)\rho^2\sin(\phi)d\rho d\phi d\Theta$$

I think that I understand how to set up the domain of this integral except for the inner integral. The question asks: "Let $D$ denote the set in $\mathbb{R^3}$ lying above the cone $z=\sqrt{x^2+y^2}$ and inside the sphere $x^2+y^2+z^2=4$. Set up the following integrals over $D$ as iterated integrals in spherical coordinates. You should think about which ones you can evaluate."

would this be correct?: $$\int_0^\pi \int_0^\frac{\pi}{4} \int_0^2 (\rho^2)\rho^2\sin(\phi)d\rho d\phi d\Theta$$

I think that I understand how to set up the domain of this integral except for the inner integral. The question asks: "Let $D$ denote the set in $\mathbb{R^3}$ lying above the cone $z=\sqrt{x^2+y^2}$ and inside the sphere $x^2+y^2+z^2=4$. Set up the following integrals over $D$ as iterated integrals in spherical coordinates. You should think about which ones you can evaluate."

would this be correct?: $$\int_0^\pi \int_0^\frac{\pi}{4} \int_0^2 (\rho^2)\rho^2\sin(\phi)d\rho d\phi d\Theta$$

comment: sorry, this is for part c.a.