Mark's Calc III - Individual question feedhttp://calc3.askbot.com/questions/Open source question and answer forum written in Python and DjangoenCopyright Askbot, 2010-2011.Thu, 17 Jul 2014 11:15:53 -0500Partial Derivativeshttp://calc3.askbot.com/question/122/partial-derivatives/So I'm working on the exam review, and I'm looking at question 3 part a. I run into issues on my partial derivatives when they include e. I ended up with $\frac {\delta f}{\delta x} = e^{xy} + xye^{xy}$ and $\frac {\delta f}{\delta y} = x^2e^{xy}$ I don't feel like thats right though, and I can't get mathematica or wolfram alpha to give me answers. Any help would be greatly appreciated! TiffanyThu, 17 Jul 2014 11:15:53 -0500http://calc3.askbot.com/question/122/Double Integralshttp://calc3.askbot.com/question/118/double-integrals/So with the problems he put on the board at the end of class today, I worked out the first double integral and was just hoping someone could verify if I'm doing it right. So he gave us the domain : ![image description](/upfiles/calc3.askbot.com/14056097985795571.gif) and the double integral as: $$\int\int x^2y\delta A$$ for which I came up with the integrals being: $$\int _0 ^2 \int _0 ^{4-x^2} x^2y \delta y \delta x$$ $$=\int _0 ^2 \frac 12x^2y^2\delta x \mid _0 ^{4-x^2}$$ $$=\int _0 ^2 \frac 12 x^2 (4-x^2)^2 \delta x$$ $$= \int _0 ^2 \frac 12 x^2(16-8x^2+x^4)\delta x$$ $$=\int _0 ^2 8x^2 -4x^4 + \frac 12 x^6 \delta x$$ $$=\frac 83 x^3 - \frac 45 x^5 + \frac {1}{14} x^7 \mid _0 ^2$$ $$= \frac 83 (8) - \frac 45(32) + \frac{1}{14}(128)$$ $$= \frac{64}{3} -\frac{128}{5} +\frac{128}{14}$$ This method seems to make sense to me(hoping that my terms of integration are correct), so I'm just hoping that someone else follows this too, or you could explain and easier way to do it. Thanks!TiffanyThu, 17 Jul 2014 10:21:11 -0500http://calc3.askbot.com/question/118/