Lagrange multipliers and their system of equationshttp://calc3.askbot.com/questions/Open source question and answer forum written in Python and DjangoenCopyright Askbot, 2010-2011.Thu, 17 Jul 2014 11:37:25 -0500Partial Derivativeshttp://calc3.askbot.com/question/122/partial-derivatives/So I'm working on the exam review, and I'm looking at question 3 part a. I run into issues on my partial derivatives when they include e. I ended up with $\frac {\delta f}{\delta x} = e^{xy} + xye^{xy}$ and $\frac {\delta f}{\delta y} = x^2e^{xy}$ I don't feel like thats right though, and I can't get mathematica or wolfram alpha to give me answers. Any help would be greatly appreciated! Thu, 17 Jul 2014 11:15:53 -0500http://calc3.askbot.com/question/122/partial-derivatives/Answer by Anonymous for Partial Derivatives http://calc3.askbot.com/question/122/partial-derivatives/?answer=123#post-id-123Actually that is perfect (I think); you are abiding by the product rule when differentiating with respect to x and treating x as a constant when differentiating with respect to y. Beautiful! :)Thu, 17 Jul 2014 11:30:05 -0500http://calc3.askbot.com/question/122/partial-derivatives/?answer=123#post-id-123Answer by Wes for Partial Derivatives http://calc3.askbot.com/question/122/partial-derivatives/?answer=124#post-id-124That is what I got! For the $\frac{df}{dx}$ I used the Product rule, or $(f*g)= f'g + fg'$, and got your answer. And for $\frac{df}{dy}$ I used the traditional rules for taking the derivative involving $e$, where we treat $x$ as a constant and bring it down. I believe I am correct, and you are too! Thu, 17 Jul 2014 11:37:25 -0500http://calc3.askbot.com/question/122/partial-derivatives/?answer=124#post-id-124