![]() | 1 | initial version | posted 2014-07-31 19:11:19 -0600 |
Ok, you take each point one at a time and get your values for a,b,c.
Starting with $ax + by + cz = 4$ and the point $(4,0,0)$, you see that with this point $x=4, y=0$ and $ z=0$.
So we get $a4 +b0 + c0 = 4$
This leaves $4a=4$, so $a=1$.
Now with the point $(0,1,0) x=0, y=1$ and $z=0 $. So we have $by=4$, so $b=4$.
With $(0,0,2)$, $x=0, y=0$ and $z=2$ leaving $cz=4$, so $c=2$.
Now with values for a,b,c, we have the equation for the plane, $x + 4y +2z = 4$.
I never would have thought of doing this and thought it was pretty neat!