Revision history [back]
 | 1 | initial version | posted 2014-07-21 11:01:34 -0600  |
To talk about this we need to remember what makes an integral improper.
An integral is improper when it is bound by an asymptote or infinity.
When $x$ and $y$ are equal to zero in this function the function will be undefined and $z$ values will become arbitrarily large as $x$ and $y$ approach zero. So your integral bounds for the $dr$ part of the problem will be at an asymptote.
This makes the integral improper.
