Q review 10

10
v = \langle 8,24 \rangle
On Y direction the displacement is given by

where u in y dir is 24 fps, a = -32.2f/s^2 (acceleration due to gravity)
When after a certain time t, the object completes its path and strikes the ground the displacement is 0
so

So total time of flight is 1.49s

On X direction the displacement is given by

where u in x dir is 8 fps, no other force is applying
and time of flight from Y dir is 1.49s

So the object land 11.93 feet away

This looks great! Note that I typically accept a=-32 f/s^2 in English units so that we get t=3/2 exactly. Not that the acceleration due to gravity really is -32 exactly, but it’s close enough for quiz purposes.