Average your name 11:00 AM

(10 pts)

For your first Stat Talk assignment, you're going to practice a basic statistical computation and type it into the forum using its typesetting tools. Here's the problem:

Use your first name to generate a list of integers by finding the position of each of up to the first five letters of your name in the alphabet. For example, my name is "Mark"; thus my list of numbers is:
[13, 1, 18 , 11].
Then, use the formulaic definitions to compute the mean and sample standard deviation of the resulting numeric data. Be sure to type out your computation as well as the result.

Comments

  • My name is Audrey so my list is:
    [1, 21, 4, 18, 5]
    The mean of those numbers is

    $(1+21+4+18+5)/5 = 49/5 ~~ 9.8.$

    The standard deviation is

    $sqrt(((9.8-1)^2 + (9.8-21)^2 + (9.8-4)^2 +(9.8-18)^2 +(9.8-5)^2)/4) ~~ 9.04.$


    This is not part of the assignment but, to place that all into the forum, I typed:

    My name is *Audrey* so my list is:
    [1, 21, 4, 18, 5]
    The mean of those numbers is 
    
    $(1+21+4+18+5)/5 = 49/5 ~~ 9.8.$
    
    The standard deviation is
    
    $sqrt(((9.8-1)^2 + (9.8-21)^2 + (9.8-4)^2 +(9.8-18)^2 +(9.8-5)^2)/4) ~~ 9.04.$
    
    mark
  • MAAMAA
    edited January 25

    My name is Mike so my list is:
    [13, 9, 11, 5]

    The mean of those numbers

    $(13+9+11+5)/4 = 9.5$

    The Standard deviation is

    $sqrt(((9.5-13)^2 + (9.5-9)^2 + (9.5-11)^2 + (9.5-5)^2)/3) ~~ 2.95.$

    mark
  • edited January 25

    My name is Anna so my list is:
    [1, 14, 14, 1]
    The mean of those numbers is

    $(1+14+14+1)/4 = 30/4 ~~ 7.5.$

    The standard deviation is

    $sqrt(((7.5-1)^2 + (7.5-14)^2 + (7.5-14)^2 +(7.5-1)^2)/3) ~~ 6.5.$

    mark
  • edited January 25

    My name is Noah so my list is:
    [14, 15, 1, 8]
    The mean of those numbers is

    $(14+15+1+8)/4 = 38/4 ~~ 9.5.$

    The standard deviation is

    $sqrt(((9.5-14)^2 + (9.5-15)^2 + (9.5-1)^2 + (9.5-8)^2)/4) ~~ 5.59.$

    mark
  • My name is Erin so my list is:
    [5, 18, 9, 14]
    The mean of those numbers is

    $(5+18+9+14)/4 = 46/4 ~~ 11.5.$

    The standard deviation is

    $sqrt(((11.5-5)^2 + (11.5-18)^2 + (11.5-9)^2 +(11.5-14)^2 )/3) ~~32.33 .$

    mark
  • My name is Cameron so my list is:
    [3,1,13,5,18]
    The mean of those numbers is:

    $(3+1+13+5+18)/5 = 42/5 = 8.4$

    The standard deviation is:

    $sqrt(((3-8.4)^2 + (1-8.4)^2 + (13-8.4)^2 + (5-8.4)^2 + (18-8.4)^2)/4) ~~ 7.22.$

    mark
  • edited January 25

    My name is "Makenna" so my list is

    [13, 1, 11, 5, 14]

    The mean of those numbers is

    $(13+1+11+5+14)/5 = 44/5 ~~ 8.8.$

    The standard deviation is

    $sqrt(((8.8-13)^2 + (8.8-1)^2 + (8.8-11)^2 +(8.8-5)^2 +(8.8-14)^2)/4) ~~ 5.59.$

    mark
  • My name is Matt so my list is:
    [13, 1, 20, 20]
    The mean of those numbers is

    $(13+1+20+20)/5 = 54/5 ~~ 10.8.$

    The standard deviation is

    $sqrt(((10.8-1)^2 + (10.8-21)^2 + (10.8-4)^2 +(10.8-18)^2 +(10.8-5)^2)/4) ~~ -1.21$

    mark
  • My name is Michaela so my list is:
    [13, 9, 3, 8, 1]
    The mean of those numbers is

    $(13+9+3+8+1)/5 = 34/5 ~~ 6.8.$

    The standard deviation is

    $sqrt( ( (6.8-13)^2 + (6.8-9)^2 + (6.8-3)^2 + (6.8-8)^2 + (6.8-1)^2)/4) ~~ 4.81.$

    mark
  • edited January 25

    my name is leah so my list is
    [12,5,1,8]
    so the mean of those numbers is
    $(12+5+1+8)/4=6.5$
    the standard deviation
    $sqrt(( (12-6.5)^2+(6.5-5)^2+(6.5-1)^2+(8-6.5)^2) /4)~~4.7$

    mark
  • edited January 25

    My name is Anthony so my list is:
    [1,14 ,20 ,8 ,15 ]
    The mean of those numbers is

    $(1+14+20+8+15)/5 = 58/5 ~~ 11.6.$

    The standard deviation is

    $sqrt(((11.6-1)^2 + (11.6-14)^2 + (11.6-20)^2 +(11.6-8)^2 +(11.6-15)^2)/4) ~~53.3 .$

    mark
  • edited January 25

    My name is Stone so my list is:
    [19, 20, 15, 14, 5]
    The mean of those numbers is:

    $(19+20+15+14+5)/5 = 73/5 = 14.6$

    And the standard deviation:

    $sqrt(((14.6-19)^2 + (14.6-20)^2 + (14.6-15)^2 + (14.6-14)^2 + (14.6-5)^2)/4) ~~ 35.3$

    mark
  • My name is Yates so my list is:
    [25, 1, 20, 5, 19]
    The mean of those numbers is

    $(25+1+20+5+19)/5 = 70/5 ~~14.$

    The standard deviation is

    $sqrt(((14-25)^2 + (14-1)^2 + (14-20)^2 +(14-5)^2 +(14-19)^2)/4) ~~ 5.19.$

    mark
  • My name is Jamia so my list is:
    [10,1,13,9,1]
    The mean of those numbers is

    $(10+1+13+9+1)/5 = 34/5 ~~ 6.8.$

    The standard deviation is

    $sqrt(((6.8-10)^2 + (6.8-1)^2 + (6.8-13)^2 +(6.8-9)^2 +(6.8-1)^2)/4) ~~ 95.57$

    mark
  • My name is Kylie so my list is:
    (11, 26, 12, 9, 5)
    The mean of those numbers is
    $(11+26+12+9+5)/5=63/5~~ 12.6$
    The standard deviation is
    $sqrt(((12.6-11)^2 + (12.6-26)^2 + (12.6-12)^2 + (12.6-9)^2+ (12.6-5)^2)/4)~~63.3.$

    mark
  • My name is Evan so my list is:
    [5, 22, 1, 14,]The mean of those numbers is

    $(4+22+1+14)/4 = 42/4 ~~ 9.8.$

    The standard deviation is

    $sqrt(((10.5-5)^2 + (10.5-22)^2 + (10.5-1)^2 +(10.5-14)^2 +)/3) ~~ 9.4.$

    mark
  • My name is Keoni so my list is:
    [11, 5, 15, 14, 9]
    The mean of those numbers is

    $(11+5+15+14+9)/5 = 54/5 ~~ 10.8 $

    The standard deviation is

    $sqrt(((10.8-11)^2 + (10.8-5)^2 + (10.8-15)^2 +(10.8-14)^2 +(10.8-9)^2)/4) ~~ 4.02.$

    mark
  • edited January 25

    My name is Phoebe, but I got by feebs so my list is:
    (6,5,5,2,19)
    the mean of those numbers is
    $(6+5+5+2+19)/4 =37/4 ~~9.25.$
    the standard deviation is
    $sqrt(((9.25-6)^2+(9.25-5)^2+(9.25-5)^2+(9.25-2)^2+(9.25-19)^2)/4)~~48.5$

    mark
  • edited January 25

    My name is Eriana so my list is
    {5,17,11,2,1}
    The mean of those numbers is
    $5+17+11+2+1 = 36/5 ~~ 7.2$

    The standard deviation is

    $sqrt(((7.2- 5)^2 + (7.2-17)^2+ (7.2-11)^2 + ( 7.2-2)^2 + (7.2-1)^2)/4)~~44.54$

    mark
  • My name is Izzy so my list is
    {9, 26, 26, 25}
    The mean of those numbers is
    9+26+26+25=86/4≈21.5
    The standard deviation is
    $sqrt(((21.5-9)^2 + (21.5-26)^2 + (21.5-26)^2 +(21.5-25)^2 ~~ 7.22.$

    mark
  • @ljurek

    I don't think you standard deviation computation is correct since you're not dividing by anything and your $~~$ sign is under the sqrt. Your mean computation has some imput issues as well.

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