# Average your name 11:00 AM

(10 pts)

For your first Stat Talk assignment, you're going to practice a basic statistical computation and type it into the forum using its typesetting tools. Here's the problem:

Use your first name to generate a list of integers by finding the position of each of up to the first five letters of your name in the alphabet. For example, my name is "Mark"; thus my list of numbers is:
[13, 1, 18 , 11].
Then, use the formulaic definitions to compute the mean and sample standard deviation of the resulting numeric data. Be sure to type out your computation as well as the result.

• My name is Audrey so my list is:
[1, 21, 4, 18, 5]
The mean of those numbers is

$(1+21+4+18+5)/5 = 49/5 ~~ 9.8.$

The standard deviation is

$sqrt(((9.8-1)^2 + (9.8-21)^2 + (9.8-4)^2 +(9.8-18)^2 +(9.8-5)^2)/4) ~~ 9.04.$

This is not part of the assignment but, to place that all into the forum, I typed:

``````My name is *Audrey* so my list is:
[1, 21, 4, 18, 5]
The mean of those numbers is

$(1+21+4+18+5)/5 = 49/5 ~~ 9.8.$

The standard deviation is

$sqrt(((9.8-1)^2 + (9.8-21)^2 + (9.8-4)^2 +(9.8-18)^2 +(9.8-5)^2)/4) ~~ 9.04.$
``````
• edited January 25

My name is Mike so my list is:
[13, 9, 11, 5]

The mean of those numbers

$(13+9+11+5)/4 = 9.5$

The Standard deviation is

$sqrt(((9.5-13)^2 + (9.5-9)^2 + (9.5-11)^2 + (9.5-5)^2)/3) ~~ 2.95.$

• edited January 25

My name is Anna so my list is:
[1, 14, 14, 1]
The mean of those numbers is

$(1+14+14+1)/4 = 30/4 ~~ 7.5.$

The standard deviation is

$sqrt(((7.5-1)^2 + (7.5-14)^2 + (7.5-14)^2 +(7.5-1)^2)/3) ~~ 6.5.$

• edited January 25

My name is Noah so my list is:
[14, 15, 1, 8]
The mean of those numbers is

$(14+15+1+8)/4 = 38/4 ~~ 9.5.$

The standard deviation is

$sqrt(((9.5-14)^2 + (9.5-15)^2 + (9.5-1)^2 + (9.5-8)^2)/4) ~~ 5.59.$

• My name is Erin so my list is:
[5, 18, 9, 14]
The mean of those numbers is

$(5+18+9+14)/4 = 46/4 ~~ 11.5.$

The standard deviation is

$sqrt(((11.5-5)^2 + (11.5-18)^2 + (11.5-9)^2 +(11.5-14)^2 )/3) ~~32.33 .$

• My name is Cameron so my list is:
[3,1,13,5,18]
The mean of those numbers is:

$(3+1+13+5+18)/5 = 42/5 = 8.4$

The standard deviation is:

$sqrt(((3-8.4)^2 + (1-8.4)^2 + (13-8.4)^2 + (5-8.4)^2 + (18-8.4)^2)/4) ~~ 7.22.$

• edited January 25

My name is "Makenna" so my list is

[13, 1, 11, 5, 14]

The mean of those numbers is

$(13+1+11+5+14)/5 = 44/5 ~~ 8.8.$

The standard deviation is

$sqrt(((8.8-13)^2 + (8.8-1)^2 + (8.8-11)^2 +(8.8-5)^2 +(8.8-14)^2)/4) ~~ 5.59.$

• My name is Matt so my list is:
[13, 1, 20, 20]
The mean of those numbers is

$(13+1+20+20)/5 = 54/5 ~~ 10.8.$

The standard deviation is

$sqrt(((10.8-1)^2 + (10.8-21)^2 + (10.8-4)^2 +(10.8-18)^2 +(10.8-5)^2)/4) ~~ -1.21$

• My name is Michaela so my list is:
[13, 9, 3, 8, 1]
The mean of those numbers is

$(13+9+3+8+1)/5 = 34/5 ~~ 6.8.$

The standard deviation is

$sqrt( ( (6.8-13)^2 + (6.8-9)^2 + (6.8-3)^2 + (6.8-8)^2 + (6.8-1)^2)/4) ~~ 4.81.$

• edited January 25

my name is leah so my list is
[12,5,1,8]
so the mean of those numbers is
$(12+5+1+8)/4=6.5$
the standard deviation
$sqrt(( (12-6.5)^2+(6.5-5)^2+(6.5-1)^2+(8-6.5)^2) /4)~~4.7$

• edited January 25

My name is Anthony so my list is:
[1,14 ,20 ,8 ,15 ]
The mean of those numbers is

$(1+14+20+8+15)/5 = 58/5 ~~ 11.6.$

The standard deviation is

$sqrt(((11.6-1)^2 + (11.6-14)^2 + (11.6-20)^2 +(11.6-8)^2 +(11.6-15)^2)/4) ~~53.3 .$

• edited January 25

My name is Stone so my list is:
[19, 20, 15, 14, 5]
The mean of those numbers is:

$(19+20+15+14+5)/5 = 73/5 = 14.6$

And the standard deviation:

$sqrt(((14.6-19)^2 + (14.6-20)^2 + (14.6-15)^2 + (14.6-14)^2 + (14.6-5)^2)/4) ~~ 35.3$

• My name is Yates so my list is:
[25, 1, 20, 5, 19]
The mean of those numbers is

$(25+1+20+5+19)/5 = 70/5 ~~14.$

The standard deviation is

$sqrt(((14-25)^2 + (14-1)^2 + (14-20)^2 +(14-5)^2 +(14-19)^2)/4) ~~ 5.19.$

• My name is Jamia so my list is:
[10,1,13,9,1]
The mean of those numbers is

$(10+1+13+9+1)/5 = 34/5 ~~ 6.8.$

The standard deviation is

$sqrt(((6.8-10)^2 + (6.8-1)^2 + (6.8-13)^2 +(6.8-9)^2 +(6.8-1)^2)/4) ~~ 95.57$

• My name is Kylie so my list is:
(11, 26, 12, 9, 5)
The mean of those numbers is
$(11+26+12+9+5)/5=63/5~~ 12.6$
The standard deviation is
$sqrt(((12.6-11)^2 + (12.6-26)^2 + (12.6-12)^2 + (12.6-9)^2+ (12.6-5)^2)/4)~~63.3.$

• My name is Evan so my list is:
[5, 22, 1, 14,]The mean of those numbers is

$(4+22+1+14)/4 = 42/4 ~~ 9.8.$

The standard deviation is

$sqrt(((10.5-5)^2 + (10.5-22)^2 + (10.5-1)^2 +(10.5-14)^2 +)/3) ~~ 9.4.$

• My name is Keoni so my list is:
[11, 5, 15, 14, 9]
The mean of those numbers is

$(11+5+15+14+9)/5 = 54/5 ~~ 10.8$

The standard deviation is

$sqrt(((10.8-11)^2 + (10.8-5)^2 + (10.8-15)^2 +(10.8-14)^2 +(10.8-9)^2)/4) ~~ 4.02.$

• edited January 25

My name is Phoebe, but I got by feebs so my list is:
(6,5,5,2,19)
the mean of those numbers is
$(6+5+5+2+19)/4 =37/4 ~~9.25.$
the standard deviation is
$sqrt(((9.25-6)^2+(9.25-5)^2+(9.25-5)^2+(9.25-2)^2+(9.25-19)^2)/4)~~48.5$

• edited January 25

My name is Eriana so my list is
{5,17,11,2,1}
The mean of those numbers is
$5+17+11+2+1 = 36/5 ~~ 7.2$

The standard deviation is

$sqrt(((7.2- 5)^2 + (7.2-17)^2+ (7.2-11)^2 + ( 7.2-2)^2 + (7.2-1)^2)/4)~~44.54$

• My name is Izzy so my list is
{9, 26, 26, 25}
The mean of those numbers is
9+26+26+25=86/4≈21.5
The standard deviation is
$sqrt(((21.5-9)^2 + (21.5-26)^2 + (21.5-26)^2 +(21.5-25)^2 ~~ 7.22.$

• @ljurek

I don't think you standard deviation computation is correct since you're not dividing by anything and your $~~$ sign is under the sqrt. Your mean computation has some imput issues as well.