# Average your name 8:00 AM

edited January 25

(10 pts)

For your first Stat Talk assignment, you're going to practice a basic statistical computation and type it into the forum using its typesetting tools. Here's the problem:

Use your first name to generate a list of integers by finding the position of each of up to the first five letters of your name in the alphabet. For example, my name is "Mark"; thus my list of numbers is:
[13, 1, 18 , 11].
Then, use the formulaic definitions to compute the mean and sample standard deviation of the resulting numeric data. Be sure to type out your computation as well as the result.

• edited January 24

My name is Audrey so my list is:
[1, 21, 4, 18, 5]
The mean of those numbers is

$(1+21+4+18+5)/5 = 49/5 ~~ 9.8.$

The standard deviation is

$sqrt(((9.8-1)^2 + (9.8-21)^2 + (9.8-4)^2 +(9.8-18)^2 +(9.8-5)^2)/4) ~~ 9.04.$

This is not part of the assignment but, to place that all into the forum, I typed:

``````My name is *Audrey* so my list is:
[1, 21, 4, 18, 5]
The mean of those numbers is

$(1+21+4+18+5)/5 = 49/5 ~~ 9.8.$

The standard deviation is

$sqrt(((9.8-1)^2 + (9.8-21)^2 + (9.8-4)^2 +(9.8-18)^2 +(9.8-5)^2)/4) ~~ 9.04.$
``````
• edited January 25

My name is Sam so my list is:
[19, 1, 13]
The mean of those numbers is 11

$(19+1+13)/3 = 33/3 ~~ 11.$

The standard deviation is

$sqrt(((19-11)^2 + (1-11)^2 + (13-11)^2) /2) ~~ 9.56.$

• edited January 25

My name is Hannah so my list is:
[8, 1, 14, 14, 1]
The mean of those numbers is

$(8+1+14+14+1)/5 = 28/5 ~~ 7.6.$

The standard deviation is

$sqrt(((7.6-8)^2 + (7.6-1)^2 + (7.6-14)^2 +(7.6-14)^2 +(7.6-1)^2)/4) ~~ 42.3.$

• edited January 25

My Name is Venecia and my list is

[22, 5, 14, 5, 3]
The mean of these numbers is

$(22+5+14+5+3)/5= 49/5= 9.8.$

The standard deviation is

$sqrt(((9.8-1)^2 + (9.8-21)^2 + (9.8-4)^2 +(9.8-18)^2 +(9.8-5)^2)/4) ~~ 9.04.$

• edited January 25

My name is Dannia so my list is:
[4, 1, 14, 14, 9, 1]
The mean of those numbers is
$(4+1+14+14+9+1)/6 = 43/6 ~~7.167$
The standard deviation is
$sqrt(((7.167-4)^2 + (7.167-1)^2 + (7.167-14)^2 + (7.167-14)^2 +(7.167-9)^2 +(7.167-1)^2)/5) ~~ 2.7.$

• edited January 25

My name is Juliette so my list is:
[10, 21, 12, 9, 18]
The mean of those numbers is

$(10+21+12+9+18)/4 = 71/4 ~~ 14.2.$

The standard deviation is

$sqrt(((14.2-10)^2 + (14.2-21)^2 + (14.2-12)^2 +(14.2-9)^2 +(14.2-18)^2)/4) ~~ 27.55.$

• edited January 25

My name is Damen so my list would be as follows:
[4, 1, 13, 5, 14]
The mean of the numbers become

$(4+1+13+5+14)/5 ~~ 7.6$

The standard deviation is

$sqrt(((7.6-4)^2 + (7.6-1)^2 + (7.6-13)^2 + (7.6-5)^2 + (7.6-14)^2)/4) ~~ 5.77$

• My name is Joshua so my list is:
[10, 15, 19, 8, 21]
The mean of those numbers is

$(10+15+19+8+21)/5 = 73/5 ~~ 14.6.$

The standard deviation is

$sqrt(((14.6-10)^2 + (14.6-15)^2 + (14.6-19)^2 +(14.6-8)^2 +(14.6-21)^2)/4) ~~ 5.59.$

• edited January 25

My name is Leland so my list is:
[12, 5, 12, 1, 14, 4]
The mean of those numbers is

$(12+5+12+1+14+5)/6 = 48/6 ~~ 8.$

The standard deviation is

$sqrt(((8-12)^2 + (8-5)^2 + (8-12)^2 + (8-1)^2 + (8-14) + (8-4)^2)/5) ~~ 5.33.$

• edited January 25

My name is laura so my list is:
[12, 1, 21, 18, 1]
The mean of those numbers is

$(12+1+21+18+1)/5 = 53/5 ~~ 10.6$

The standard deviation is

$sqrt(((10.6-12)^2 + (10.6-1)^2 + (10.6-21)^2 +(10.6-18)^2 +(10.6-1)^2)/4) ~~ 9.34.$

• edited January 25

My name is Madyson, but my nickname is Mady so my list is:
[13,1,4,25]

$(13+1+4+25)/4= 43/4 ~~10.75.$

The Standard Deviation is

$sqrt (((10.75-13)^2 + (10.75-1)^2 + (10.75- 4)^2 + (10.75- 25)^2)/ 4) ~~ 10.78.$

• My name is Elaina my list is
[5,12,1,9,14]
The mean of those numbers is
$(5+12+1+9+14)/5 = 41/5 ~~ 8.2.$

The standard deviation is

$sqrt(((8.2-5)^2 + (8.2-12)^2 + (8.2-1)^2 +(8.2-9)^2 +(8.2-14)^2)/4) ~~ 9.25.$

• edited January 29

My name is Lindie so my list is:
[12, 9, 14, 4, 9, 5]
The mean of those numbers is

$(12+9+14+4+9+5)/6 = 49/6 ~~ 8.1.$

The standard deviation is

$sqrt(((8.1-12)^2 + (8.1-9)^2 + (8.1-14)^2 +(8.1-4)^2 +(8.1-9)^2) + (8.1-5)^2 )/5 ~~ 14.30 .$

• edited January 25

My name is Collin, so my list is:

[3, 15, 12, 12, 9]

The mean of those numbers is:

$(3+15+12+12+9)/5 = 51/5 ~~ 10.2.$

The standard deviation is:

$sqrt(((10.2-3)^2 + (10.2-15)^2 + (10.2-12)^2 +(10.2-12)^2 +(10.2-9)^2)/4) ~~ 9.04.$

• edited January 25

My name is Katelynne so my list is:
[11, 1, 20, 5, 12]
The mean of those numbers is

$(11+1+20+5+12)/5 = 49/4 ~~ 12.25.$

The standard deviation is

$sqrt(((12.25-11)^2 + (12.25-1)^2 + (12.25-20)^2 +(12.25-5)^2 +(12.25-12)^2)/4) ~~ 60.203125.$

• My name is Victoria so my list is:
[12, 9, 3, 15, 10]
The mean of those numbers is

$(22+9+3+20+15)/5 = 69/5 ~~ 13.8.$

The standard deviation is

$sqrt(((13.8-22)^2 + (13.8-9)^2 + (13.8-3)^2 +(13.8-20)^2 +(13.8-15)^2)/4) ~~ 61.7.$