An archived instance of a Discrete forum

Nine game series

mark

The first World Series was played in 1903 and was a rare best of nine game format. Thus, the first team to win 5 games was declared the winner. As it turned out, the Boston Americans defeated the Pittsburgh Pirates in 8 games. The exact sequence of games was:

Game 1 Game 2 Game 3 Game 4 Game 5 Game 6 Game 7 Game 8
P B P P B B B B

How many sequences like this are there where Team B beats Team P in 8 games of a 9 game series?

ksimmon1

Since we want to find the sequences where Team B beats Team P in the 8th game, that means they have to win 5 games total including Game 8.

I set this up as:

{8\choose5} = \frac{8!}{5!3!} = 56
mark

@ksimmon1 I think that 8\choose5 includes, for example,

Game 1 Game 2 Game 3 Game 4 Game 5 Game 6 Game 7 Game 8
P B P B B B B P

That series really would’ve ended in game 7

ksimmon1

Instead of using the formula:

n\choose{k}

Would this formula work?

n-1\choose{k-1}

Because at Game 7, Team B would have had to win exactly 4 games before going into Game 8?

If this formula works the answer would be:

{7\choose4} = \frac{7!}{4!3!} = 35