mark
Express
20\choose17
as a product of at most 3 integers.
An archived instance of a Discrete forum
Binomial simplification
ksimmon1
{20\choose17} = \frac{20!}{17!3!}=\frac{20\cdot19\cdot18\cdot17!}{17!3!} = \frac{20\cdot19\cdot18}{6} = 20\cdot19\cdot3