An archived instance of discourse for discussion in a Fractal Introductory Colloquium.

Your personal spiral

mark

Let's generate your own personal fractal spiral using the IFS Visualizer as follows. If we set the IFS Visualizer to the spiral example, it looks like we need three things:

  • An $r_0$ to set the size of the big piece,
  • an $r_1$ to set the size of the small pice, and
  • a $t$ to set the rotation.

To generate these, we'll use a little numerology. First, let $n$ be the number name associated with your first name generated in the standard but crazy way. This should be a two or three digit integer. Then

  • Generate $r_0$ by slapping a decimal point in front of $n$,
  • let $r_1=1-r_0$, and
  • let $t = n^{\circ}$.

Using these, have a go!

Audrey

OK - here's my attempt. (Of course, the first thing I did was give a "like" to the original question, because that's the polite thing to do.)

First, my first name is Audrey and the letters of my name occur at the positions 1, 21, 4, 18, 5, and 25 of the alphabet. The sum of those numbers gives me $n=74$. Thus, I get

  • $r_0=0.74$,
  • $r_1=0.26$, and
  • $t=74^{\circ}$.

Plugging these into the IFS visualizer, I get a picture that looks like so:

Vanderbilt

OK, if I use the same method as Audrey to find a number "n", here's what I get:

HORACE:
$8+15+18+1+3+5=50$

Wow, what're the odds?

Using $n=50$, here're the rest of the numbers:
$r_0=0.5$
$r_1=0.5$
$t=50^∘$


Here's the picture that's generated:


Looks cool! :smiley:

sjenkin1

Okay, here we go

Scroll down for the most complex spiral ever to grace your vision....

(Not really)


S=19
A=1
M=13
So my number was 33.
$r_0=.33$
$r_1=.66$
$t=33deg$







eolberdi

ERICA= 5+9+18+3+1=36
$r_0$=.36
$r_1$=.64
$t$= 36 degrees




kadams

Mine was similar to Horace's.

KYLE:
12+25+13+5=53

So,
$r_0=0.53$
$r_1=0.47$
$t=47$ degrees




Vanderbilt

For the "Fractal Dimension" for my personal function is:
(since both "r" values are the same)

$log(2)/log(1/0.5) = log(2)/log(2) = 1$

So if I'm not mistaken, the fractal dimension is 1?

cbozarth

Cynthia= 3+25+14+20+8+9+1= 80,
so,
$r_0=0.80$
$r_1=0.20$ and
$t=80$ degrees



tmorse

TRISTAN:
$20 + 18 + 9 + 19 + 20 + 1 + 14 = 101$

So,
$r_0 = 0.101$
$r_1 = 0.899$
$t = 101$ degrees


The fractal dimension for my spiral is 1! Holy smokes, can you believe it??

mark

@tmorse The problem states that you "Generate $r_0$ by slapping a decimal point in front of $n$". Thus, I think your $r_0$ should be $0.101$.

tmorse

Thanks! I was wondering if I was supposed to move the decimal point 2 or 3 places, since I'm the only one with a 3 digit number so far. I'll try it out with 3.

dcutchen

D = 4
E = 5
V = 22
I = 9
N = 14
So my number was 54
So,
$r_0=0.54$
$r_1=0.46$
$t=54$ $degrees$


And My dimension is 1 because of math.










eolberdi

My fractal dimension is 1

jhoneyc1

My name happens to be Jacob, meaning that my special number is 31.

If you input the following values...

  • $r_0 = 0.31$

  • $r_1 = 0.69$

  • $t = 31^{\circ}$

...you will get the following spiral.


katyagreb

At first I used my nickname Katya.
Katya = 58
$r_o$=.58
$r_1$= .42
$t$= 58 degrees






however after reviewing everyone else's I figured this one was not very special and decided to use Ekaterina.
Ekaterina = 84
$r_0$ = .84
$r_1$ = .16
$t$ = 84 degrees






hcary

HOPE= 8+15+16+5=44
$r_0=.44$
$r_1=.56$
$t=44$





lgibbs

Levi= 12+5+22+9=48
$n_0=.48$
$n_1=.54$
$t=48$